Solve (x+2)^2+(4+3)^2=16

$$( x + 2 ) ^ { 2 } + ( 4 + 3 ) ^ { 2 } = 16$$

Solve for x (complex solution)

$$x=-\sqrt{33}i-2\approx -2-5.744562647i$$

$$x=-2+\sqrt{33}i\approx -2+5.744562647i$$

Steps by Finding Square Root

Subtracting 49 from itself leaves 0.

$$\left(x+2\right)^{2}=16-49$$

Subtract 49 from 16.

$$\left(x+2\right)^{2}=-33$$

Take the square root of both sides of the equation.

$$x+2=\sqrt{33}i x+2=-\sqrt{33}i$$

Subtract 2 from both sides of the equation.

$$x+2-2=\sqrt{33}i-2 x+2-2=-\sqrt{33}i-2$$

Subtracting 2 from itself leaves 0.

$$x=\sqrt{33}i-2 x=-\sqrt{33}i-2$$

Subtract 2 from i\sqrt{33}.

$$x=-2+\sqrt{33}i$$

Subtract 2 from -i\sqrt{33}.

$$x=-\sqrt{33}i-2$$

The equation is now solved.

$$x=-2+\sqrt{33}i x=-\sqrt{33}i-2$$