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x^{2}+4x\sqrt{3}+4\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\sqrt{3}\right)^{2}.
x^{2}+4x\sqrt{3}+4\times 3
The square of \sqrt{3} is 3.
x^{2}+4x\sqrt{3}+12
Multiply 4 and 3 to get 12.
x^{2}+4x\sqrt{3}+4\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\sqrt{3}\right)^{2}.
x^{2}+4x\sqrt{3}+4\times 3
The square of \sqrt{3} is 3.
x^{2}+4x\sqrt{3}+12
Multiply 4 and 3 to get 12.