Solve (x+1)y^2=12

$$( x + 1 ) y ^ { 2 } = 12$$

Solve for x

$$x=-1+\frac{12}{y^{2}}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+1 by y^{2}.

$$xy^{2}+y^{2}=12$$

Subtract y^{2} from both sides.

$$xy^{2}=12-y^{2}$$

The equation is in standard form.

$$y^{2}x=12-y^{2}$$

Divide both sides by y^{2}.

$$\frac{y^{2}x}{y^{2}}=\frac{12-y^{2}}{y^{2}}$$

Dividing by y^{2} undoes the multiplication by y^{2}.

$$x=\frac{12-y^{2}}{y^{2}}$$

Divide 12-y^{2} by y^{2}.

$$x=-1+\frac{12}{y^{2}}$$

Solve for y (complex solution)

$$y=-2\sqrt{3}\left(x+1\right)^{-\frac{1}{2}}$$

$$y=2\sqrt{3}\left(x+1\right)^{-\frac{1}{2}}\text{, }x\neq -1$$

Solve for y

$$y=2\sqrt{\frac{3}{x+1}}$$

$$y=-2\sqrt{\frac{3}{x+1}}\text{, }x>-1$$