Solve (x+1)(y+1)=2

$$( x + 1 ) ( y + 1 ) = 2$$

Solve for x

$$x=-\frac{y-1}{y+1}$$

$$y\neq -1$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+1 by y+1.

$$xy+x+y+1=2$$

Subtract y from both sides.

$$xy+x+1=2-y$$

Subtract 1 from both sides.

$$xy+x=2-y-1$$

Subtract 1 from 2 to get 1.

$$xy+x=1-y$$

Combine all terms containing x.

$$\left(y+1\right)x=1-y$$

Divide both sides by y+1.

$$\frac{\left(y+1\right)x}{y+1}=\frac{1-y}{y+1}$$

Dividing by y+1 undoes the multiplication by y+1.

$$x=\frac{1-y}{y+1}$$

Solve for y

$$y=-\frac{x-1}{x+1}$$

$$x\neq -1$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+1 by y+1.

$$xy+x+y+1=2$$

Subtract x from both sides.

$$xy+y+1=2-x$$

Subtract 1 from both sides.

$$xy+y=2-x-1$$

Subtract 1 from 2 to get 1.

$$xy+y=1-x$$

Combine all terms containing y.

$$\left(x+1\right)y=1-x$$

Divide both sides by x+1.

$$\frac{\left(x+1\right)y}{x+1}=\frac{1-x}{x+1}$$

Dividing by x+1 undoes the multiplication by x+1.

$$y=\frac{1-x}{x+1}$$