Solve (x+1)(x-2)=x^2+4x+8

$$( x + 1 ) ( x - 2 ) = x ^ { 2 } + 4 x + 8$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+1 by x-2 and combine like terms.

$$x^{2}-x-2=x^{2}+4x+8$$

Subtract x^{2} from both sides.

$$x^{2}-x-2-x^{2}=4x+8$$

Combine x^{2} and -x^{2} to get 0.

$$-x-2=4x+8$$

Subtract 4x from both sides.

$$-x-2-4x=8$$

Combine -x and -4x to get -5x.

$$-5x-2=8$$

Add 2 to both sides.

$$-5x=8+2$$

Add 8 and 2 to get 10.

$$-5x=10$$

Divide both sides by -5.

$$x=\frac{10}{-5}$$

Divide 10 by -5 to get -2.

$$x=-2$$