Solve (x+1)(4x-1)+(x+1)(2x-5)

$$( x + 1 ) ( 4 x - 1 ) + ( x + 1 ) ( 2 x - 5 )$$

Evaluate

$$6\left(x^{2}-1\right)$$

Solution Steps

Apply the distributive property by multiplying each term of x+1 by each term of 4x-1.

$$4x^{2}-x+4x-1+\left(x+1\right)\left(2x-5\right)$$

Combine -x and 4x to get 3x.

$$4x^{2}+3x-1+\left(x+1\right)\left(2x-5\right)$$

Apply the distributive property by multiplying each term of x+1 by each term of 2x-5.

$$4x^{2}+3x-1+2x^{2}-5x+2x-5$$

Combine -5x and 2x to get -3x.

$$4x^{2}+3x-1+2x^{2}-3x-5$$

Combine 4x^{2} and 2x^{2} to get 6x^{2}.

$$6x^{2}+3x-1-3x-5$$

Combine 3x and -3x to get 0.

$$6x^{2}-1-5$$

Subtract 5 from -1 to get -6.

$$6x^{2}-6$$

Expand

$$6x^{2}-6$$

Solution Steps

Apply the distributive property by multiplying each term of x+1 by each term of 4x-1.

$$4x^{2}-x+4x-1+\left(x+1\right)\left(2x-5\right)$$

Combine -x and 4x to get 3x.

$$4x^{2}+3x-1+\left(x+1\right)\left(2x-5\right)$$

Apply the distributive property by multiplying each term of x+1 by each term of 2x-5.

$$4x^{2}+3x-1+2x^{2}-5x+2x-5$$

Combine -5x and 2x to get -3x.

$$4x^{2}+3x-1+2x^{2}-3x-5$$

Combine 4x^{2} and 2x^{2} to get 6x^{2}.

$$6x^{2}+3x-1-3x-5$$

Combine 3x and -3x to get 0.

$$6x^{2}-1-5$$

Subtract 5 from -1 to get -6.

$$6x^{2}-6$$