Solve (x+1)*(y-1)=4

$$( x + 1 ) \cdot ( y - 1 ) = 4$$

Solve for x

$$x=-\frac{y-5}{y-1}$$

$$y\neq 1$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+1 by y-1.

$$xy-x+y-1=4$$

Subtract y from both sides.

$$xy-x-1=4-y$$

Add 1 to both sides.

$$xy-x=4-y+1$$

Add 4 and 1 to get 5.

$$xy-x=5-y$$

Combine all terms containing x.

$$\left(y-1\right)x=5-y$$

Divide both sides by y-1.

$$\frac{\left(y-1\right)x}{y-1}=\frac{5-y}{y-1}$$

Dividing by y-1 undoes the multiplication by y-1.

$$x=\frac{5-y}{y-1}$$

Solve for y

$$y=\frac{x+5}{x+1}$$

$$x\neq -1$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+1 by y-1.

$$xy-x+y-1=4$$

Add x to both sides.

$$xy+y-1=4+x$$

Add 1 to both sides.

$$xy+y=4+x+1$$

Add 4 and 1 to get 5.

$$xy+y=5+x$$

Combine all terms containing y.

$$\left(x+1\right)y=5+x$$

The equation is in standard form.

$$\left(x+1\right)y=x+5$$

Divide both sides by x+1.

$$\frac{\left(x+1\right)y}{x+1}=\frac{x+5}{x+1}$$

Dividing by x+1 undoes the multiplication by x+1.

$$y=\frac{x+5}{x+1}$$