Solve (x+1)^2=x^2-3

$$( x + 1 ) ^ { 2 } = x ^ { 2 } - 3$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.

$$x^{2}+2x+1=x^{2}-3$$

Subtract x^{2} from both sides.

$$x^{2}+2x+1-x^{2}=-3$$

Combine x^{2} and -x^{2} to get 0.

$$2x+1=-3$$

Subtract 1 from both sides.

$$2x=-3-1$$

Subtract 1 from -3 to get -4.

$$2x=-4$$

Divide both sides by 2.

$$x=\frac{-4}{2}$$

Divide -4 by 2 to get -2.

$$x=-2$$