Solve (x+1)^2=x^2+x+6

$$( x + 1 ) ^ { 2 } = x ^ { 2 } + x + 6$$

Solve for x

$$x=5$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.

$$x^{2}+2x+1=x^{2}+x+6$$

Subtract x^{2} from both sides.

$$x^{2}+2x+1-x^{2}=x+6$$

Combine x^{2} and -x^{2} to get 0.

$$2x+1=x+6$$

Subtract x from both sides.

$$2x+1-x=6$$

Combine 2x and -x to get x.

$$x+1=6$$

Subtract 1 from both sides.

$$x=6-1$$

Subtract 1 from 6 to get 5.

$$x=5$$