Solve (x+1)^2=13

$$( x + 1 ) ^ { 2 } = 13$$

Solve for x

$$x=\sqrt{13}-1\approx 2.605551275$$

$$x=-\left(\sqrt{13}+1\right)\approx -4.605551275$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x+1=\sqrt{13} x+1=-\sqrt{13}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\sqrt{13}-1 x+1-1=-\sqrt{13}-1$$

Subtracting 1 from itself leaves 0.

$$x=\sqrt{13}-1 x=-\sqrt{13}-1$$