Solve (x+1)^2=10

$$( x + 1 ) ^ { 2 } = 10$$

Solve for x

$$x=\sqrt{10}-1\approx 2.16227766$$

$$x=-\left(\sqrt{10}+1\right)\approx -4.16227766$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x+1=\sqrt{10} x+1=-\sqrt{10}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\sqrt{10}-1 x+1-1=-\sqrt{10}-1$$

Subtracting 1 from itself leaves 0.

$$x=\sqrt{10}-1 x=-\sqrt{10}-1$$