Solve (x+0.7)^2+4=6.25

$$( x + 0.7 ) ^ { 2 } + 4 = 6.25$$

Solve for x

$$x=0.8$$

$$x=-2.2$$

Steps by Finding Square Root

Subtract 4 from both sides of the equation.

$$\left(x+0.7\right)^{2}+4-4=6.25-4$$

Subtracting 4 from itself leaves 0.

$$\left(x+0.7\right)^{2}=6.25-4$$

Subtract 4 from 6.25.

$$\left(x+0.7\right)^{2}=2.25$$

Take the square root of both sides of the equation.

$$x+0.7=\frac{3}{2} x+0.7=-\frac{3}{2}$$

Subtract 0.7 from both sides of the equation.

$$x+0.7-0.7=\frac{3}{2}-0.7 x+0.7-0.7=-\frac{3}{2}-0.7$$

Subtracting 0.7 from itself leaves 0.

$$x=\frac{3}{2}-0.7 x=-\frac{3}{2}-0.7$$

Subtract 0.7 from \frac{3}{2} by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.

$$x=\frac{4}{5}$$

Subtract 0.7 from -\frac{3}{2} by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.

$$x=-\frac{11}{5}$$

The equation is now solved.

$$x=\frac{4}{5} x=-\frac{11}{5}$$