Evaluate
2x^{2}+\sqrt{5}x-5
Differentiate w.r.t. x
4x+\sqrt{5}
Graph
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2x^{2}-x\sqrt{5}+2\sqrt{5}x-\left(\sqrt{5}\right)^{2}
Apply the distributive property by multiplying each term of x+\sqrt{5} by each term of 2x-\sqrt{5}.
2x^{2}+x\sqrt{5}-\left(\sqrt{5}\right)^{2}
Combine -x\sqrt{5} and 2\sqrt{5}x to get x\sqrt{5}.
2x^{2}+x\sqrt{5}-5
The square of \sqrt{5} is 5.
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