Solve (x+1/5)^2=7/25

$$( x + \frac { 1 } { 5 } ) ^ { 2 } = \frac { 7 } { 25 }$$

Solve for x

$$x=\frac{\sqrt{7}-1}{5}\approx 0.329150262$$

$$x=\frac{-\sqrt{7}-1}{5}\approx -0.729150262$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x+\frac{1}{5}=\frac{\sqrt{7}}{5} x+\frac{1}{5}=-\frac{\sqrt{7}}{5}$$

Subtract \frac{1}{5} from both sides of the equation.

$$x+\frac{1}{5}-\frac{1}{5}=\frac{\sqrt{7}}{5}-\frac{1}{5} x+\frac{1}{5}-\frac{1}{5}=-\frac{\sqrt{7}}{5}-\frac{1}{5}$$

Subtracting \frac{1}{5} from itself leaves 0.

$$x=\frac{\sqrt{7}}{5}-\frac{1}{5} x=-\frac{\sqrt{7}}{5}-\frac{1}{5}$$

Subtract \frac{1}{5} from \frac{\sqrt{7}}{5}.

$$x=\frac{\sqrt{7}-1}{5}$$

Subtract \frac{1}{5} from -\frac{\sqrt{7}}{5}.

$$x=\frac{-\sqrt{7}-1}{5}$$

The equation is now solved.

$$x=\frac{\sqrt{7}-1}{5} x=\frac{-\sqrt{7}-1}{5}$$