Solve (v+9)^2-48=0

$$( v + 9 ) ^ { 2 } - 48 = 0$$

Solve for v

$$v=4\sqrt{3}-9\approx -2.07179677$$

$$v=-4\sqrt{3}-9\approx -15.92820323$$

Steps by Finding Square Root

Add 48 to both sides of the equation.

$$\left(v+9\right)^{2}-48+48=48$$

Subtracting 48 from itself leaves 0.

$$\left(v+9\right)^{2}=48$$

Take the square root of both sides of the equation.

$$v+9=4\sqrt{3} v+9=-4\sqrt{3}$$

Subtract 9 from both sides of the equation.

$$v+9-9=4\sqrt{3}-9 v+9-9=-4\sqrt{3}-9$$

Subtracting 9 from itself leaves 0.

$$v=4\sqrt{3}-9 v=-4\sqrt{3}-9$$