Solve (u^{3}v^2*2v^0*2v^-4)^0

$$( u ^ { 3 } v ^ { 2 } \cdot 2 v ^ { 0 } \cdot 2 v ^ { - 4 } ) ^ { 0 }$$

Evaluate

$$1$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 0 to get 2.

$$\left(u^{3}v^{2}\times 2\times 2v^{-4}\right)^{0}$$

To multiply powers of the same base, add their exponents. Add 2 and -4 to get -2.

$$\left(u^{3}v^{-2}\times 2\times 2\right)^{0}$$

Multiply 2 and 2 to get 4.

$$\left(u^{3}v^{-2}\times 4\right)^{0}$$

Calculate u^{3}v^{-2}\times 4 to the power of 0 and get 1.

$$1$$

Factor

$$1$$