Solve (t-0.3)(t-0.3)

$$( t - 0.3 ) ( t - 0.3 )$$

Evaluate

$$\left(t-0.3\right)^{2}$$

Solution Steps

Multiply t-0.3 and t-0.3 to get \left(t-0.3\right)^{2}.

$$\left(t-0.3\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(t-0.3\right)^{2}.

$$t^{2}-0.6t+0.09$$

Expand

$$t^{2}-\frac{3t}{5}+0.09$$

Solution Steps

Multiply t-0.3 and t-0.3 to get \left(t-0.3\right)^{2}.

$$\left(t-0.3\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(t-0.3\right)^{2}.

$$t^{2}-0.6t+0.09$$