Solve (t+3)(t-1/7)

$$( t + 3 ) ( t - \frac { 1 } { 7 } )$$

Evaluate

$$t^{2}+\frac{20t}{7}-\frac{3}{7}$$

Solution Steps

Apply the distributive property by multiplying each term of t+3 by each term of t-\frac{1}{7}.

$$t^{2}+t\left(-\frac{1}{7}\right)+3t+3\left(-\frac{1}{7}\right)$$

Combine t\left(-\frac{1}{7}\right) and 3t to get \frac{20}{7}t.

$$t^{2}+\frac{20}{7}t+3\left(-\frac{1}{7}\right)$$

Express 3\left(-\frac{1}{7}\right) as a single fraction.

$$t^{2}+\frac{20}{7}t+\frac{3\left(-1\right)}{7}$$

Multiply 3 and -1 to get -3.

$$t^{2}+\frac{20}{7}t+\frac{-3}{7}$$

Fraction \frac{-3}{7} can be rewritten as -\frac{3}{7} by extracting the negative sign.

$$t^{2}+\frac{20}{7}t-\frac{3}{7}$$

Expand

$$t^{2}+\frac{20t}{7}-\frac{3}{7}$$

Solution Steps

Apply the distributive property by multiplying each term of t+3 by each term of t-\frac{1}{7}.

$$t^{2}+t\left(-\frac{1}{7}\right)+3t+3\left(-\frac{1}{7}\right)$$

Combine t\left(-\frac{1}{7}\right) and 3t to get \frac{20}{7}t.

$$t^{2}+\frac{20}{7}t+3\left(-\frac{1}{7}\right)$$

Express 3\left(-\frac{1}{7}\right) as a single fraction.

$$t^{2}+\frac{20}{7}t+\frac{3\left(-1\right)}{7}$$

Multiply 3 and -1 to get -3.

$$t^{2}+\frac{20}{7}t+\frac{-3}{7}$$

Fraction \frac{-3}{7} can be rewritten as -\frac{3}{7} by extracting the negative sign.

$$t^{2}+\frac{20}{7}t-\frac{3}{7}$$