Solve (s^{2})^3*5(r^0)^3*rs^2quad0

$$( s ^ { 2 } ) ^ { 3 } \times 5 ( r ^ { 0 } ) ^ { 3 } \times r s ^ { 2 } \quad 0$$

Evaluate

$$0$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$s^{6}\times 5\left(r^{0}\right)^{3}rs^{2}\times 0$$

To raise a power to another power, multiply the exponents. Multiply 0 and 3 to get 0.

$$s^{6}\times 5r^{0}rs^{2}\times 0$$

To multiply powers of the same base, add their exponents. Add 6 and 2 to get 8.

$$s^{8}\times 5r^{0}r\times 0$$

To multiply powers of the same base, add their exponents. Add 0 and 1 to get 1.

$$s^{8}\times 5r^{1}\times 0$$

Calculate r to the power of 1 and get r.

$$s^{8}\times 5r\times 0$$

Multiply 5 and 0 to get 0.

$$s^{8}\times 0r$$

Anything times zero gives zero.

$$0$$

Factor

$$0$$