Solve (s+3*2div2)*(4div2-3+6)div(7-8div2-2)^2

$$( s + 3 \cdot 2 \div 2 ) * ( 4 \div 2 - 3 + 6 ) \div ( 7 - 8 \div 2 - 2 ) ^ { 2 }$$

Evaluate

$$5\left(s+3\right)$$

Solution Steps

Cancel out 2 and 2.

$$\frac{\left(s+3\right)\left(\frac{4}{2}-3+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Divide 4 by 2 to get 2.

$$\frac{\left(s+3\right)\left(2-3+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Subtract 3 from 2 to get -1.

$$\frac{\left(s+3\right)\left(-1+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Add -1 and 6 to get 5.

$$\frac{\left(s+3\right)\times 5}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Divide 8 by 2 to get 4.

$$\frac{\left(s+3\right)\times 5}{\left(7-4-2\right)^{2}}$$

Subtract 4 from 7 to get 3.

$$\frac{\left(s+3\right)\times 5}{\left(3-2\right)^{2}}$$

Subtract 2 from 3 to get 1.

$$\frac{\left(s+3\right)\times 5}{1^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{\left(s+3\right)\times 5}{1}$$

Anything divided by one gives itself.

$$\left(s+3\right)\times 5$$

Use the distributive property to multiply s+3 by 5.

$$5s+15$$

Expand

$$5s+15$$

Solution Steps

Cancel out 2 and 2.

$$\frac{\left(s+3\right)\left(\frac{4}{2}-3+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Divide 4 by 2 to get 2.

$$\frac{\left(s+3\right)\left(2-3+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Subtract 3 from 2 to get -1.

$$\frac{\left(s+3\right)\left(-1+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Add -1 and 6 to get 5.

$$\frac{\left(s+3\right)\times 5}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Divide 8 by 2 to get 4.

$$\frac{\left(s+3\right)\times 5}{\left(7-4-2\right)^{2}}$$

Subtract 4 from 7 to get 3.

$$\frac{\left(s+3\right)\times 5}{\left(3-2\right)^{2}}$$

Subtract 2 from 3 to get 1.

$$\frac{\left(s+3\right)\times 5}{1^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{\left(s+3\right)\times 5}{1}$$

Anything divided by one gives itself.

$$\left(s+3\right)\times 5$$

Use the distributive property to multiply s+3 by 5.

$$5s+15$$