Solve (p^3-3)^2

$$( p ^ { 3 } - 3 ) ^ { 2 }$$

Expand

$$p^{6}-6p^{3}+9$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(p^{3}-3\right)^{2}.

$$\left(p^{3}\right)^{2}-6p^{3}+9$$

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$p^{6}-6p^{3}+9$$

Evaluate

$$\left(p^{3}-3\right)^{2}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(p^{3}-3\right)^{2}.

$$\left(p^{3}\right)^{2}-6p^{3}+9$$

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$p^{6}-6p^{3}+9$$