Solve (n-6)(n-1/2)

$$( n - 6 ) ( n - \frac { 1 } { 2 } )$$

Evaluate

$$n^{2}-\frac{13n}{2}+3$$

Solution Steps

Apply the distributive property by multiplying each term of n-6 by each term of n-\frac{1}{2}.

$$n^{2}+n\left(-\frac{1}{2}\right)-6n-6\left(-\frac{1}{2}\right)$$

Combine n\left(-\frac{1}{2}\right) and -6n to get -\frac{13}{2}n.

$$n^{2}-\frac{13}{2}n-6\left(-\frac{1}{2}\right)$$

Express -6\left(-\frac{1}{2}\right) as a single fraction.

$$n^{2}-\frac{13}{2}n+\frac{-6\left(-1\right)}{2}$$

Multiply -6 and -1 to get 6.

$$n^{2}-\frac{13}{2}n+\frac{6}{2}$$

Divide 6 by 2 to get 3.

$$n^{2}-\frac{13}{2}n+3$$

Expand

$$n^{2}-\frac{13n}{2}+3$$

Solution Steps

Apply the distributive property by multiplying each term of n-6 by each term of n-\frac{1}{2}.

$$n^{2}+n\left(-\frac{1}{2}\right)-6n-6\left(-\frac{1}{2}\right)$$

Combine n\left(-\frac{1}{2}\right) and -6n to get -\frac{13}{2}n.

$$n^{2}-\frac{13}{2}n-6\left(-\frac{1}{2}\right)$$

Express -6\left(-\frac{1}{2}\right) as a single fraction.

$$n^{2}-\frac{13}{2}n+\frac{-6\left(-1\right)}{2}$$

Multiply -6 and -1 to get 6.

$$n^{2}-\frac{13}{2}n+\frac{6}{2}$$

Divide 6 by 2 to get 3.

$$n^{2}-\frac{13}{2}n+3$$