Solve (n^2y)2pir=80

$$( n ^ { 2 } y ) 2 \pi r = 80$$

Solve for r

$$r=\frac{40}{\pi yn^{2}}$$

$$y\neq 0\text{ and }n\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$2\pi yn^{2}r=80$$

Divide both sides by 2n^{2}y\pi .

$$\frac{2\pi yn^{2}r}{2\pi yn^{2}}=\frac{80}{2\pi yn^{2}}$$

Dividing by 2n^{2}y\pi undoes the multiplication by 2n^{2}y\pi .

$$r=\frac{80}{2\pi yn^{2}}$$

Divide 80 by 2n^{2}y\pi .

$$r=\frac{40}{\pi yn^{2}}$$

Solve for n

$$n=2\sqrt{\frac{10}{\pi ry}}$$

$$n=-2\sqrt{\frac{10}{\pi ry}}\text{, }\left(r>0\text{ and }y>0\right)\text{ or }\left(y<0\text{ and }r<0\right)$$