Solve (n^{1}-16b^{2}+09x^2)-108a^2-b^2+17c^2

$$( n ^ { 1 } - 16 b ^ { 2 } + 09 x ^ { 2 } ) - 108 a ^ { 2 } - b ^ { 2 } + 17 c ^ { 2 }$$

Evaluate

$$n+17c^{2}-17b^{2}-108a^{2}$$

Solution Steps

Calculate n to the power of 1 and get n.

$$n-16b^{2}+0\times 9x^{2}-108a^{2}-b^{2}+17c^{2}$$

Multiply 0 and 9 to get 0.

$$n-16b^{2}+0x^{2}-108a^{2}-b^{2}+17c^{2}$$

Anything times zero gives zero.

$$n-16b^{2}+0-108a^{2}-b^{2}+17c^{2}$$

Combine -16b^{2} and -b^{2} to get -17b^{2}.

$$n-17b^{2}+0-108a^{2}+17c^{2}$$

Anything plus zero gives itself.

$$n-17b^{2}-108a^{2}+17c^{2}$$

Differentiate w.r.t. c

$$34c$$