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n^{3}-512
Multiply and combine like terms.
\left(n-8\right)\left(n^{2}+8n+64\right)
Rewrite n^{3}-512 as n^{3}-8^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial n^{2}+8n+64 is not factored since it does not have any rational roots.
n^{3}-512
Calculate 8 to the power of 3 and get 512.