Solve (n+6)^2+3=20

$$( n + 6 ) ^ { 2 } + 3 = 20$$

Solve for n

$$n=\sqrt{17}-6\approx -1.876894374$$

$$n=-\left(\sqrt{17}+6\right)\approx -10.123105626$$

Steps by Finding Square Root

Subtract 3 from both sides of the equation.

$$\left(n+6\right)^{2}+3-3=20-3$$

Subtracting 3 from itself leaves 0.

$$\left(n+6\right)^{2}=20-3$$

Subtract 3 from 20.

$$\left(n+6\right)^{2}=17$$

Take the square root of both sides of the equation.

$$n+6=\sqrt{17} n+6=-\sqrt{17}$$

Subtract 6 from both sides of the equation.

$$n+6-6=\sqrt{17}-6 n+6-6=-\sqrt{17}-6$$

Subtracting 6 from itself leaves 0.

$$n=\sqrt{17}-6 n=-\sqrt{17}-6$$