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\left(m-2\right)^{2}=0
To solve the inequality, factor the left hand side. Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
m=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\times 1\times 4}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -4 for b, and 4 for c in the quadratic formula.
m=\frac{4±0}{2}
Do the calculations.
m=2
Solutions are the same.
\left(m-2\right)^{2}\geq 0
Rewrite the inequality by using the obtained solutions.
m\in \mathrm{R}
Inequality holds for m\in \mathrm{R}.