Solve (m+5)x-m^2+25=0

$$( m + 5 ) x - m ^ { 2 } + 25 = 0$$

Solve for x (complex solution)

$$\left\{\begin{matrix}\\x=m-5\text{, }&\text{unconditionally}\\x\in \mathrm{C}\text{, }&m=-5\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply m+5 by x.

$$mx+5x-m^{2}+25=0$$

Add m^{2} to both sides. Anything plus zero gives itself.

$$mx+5x+25=m^{2}$$

Subtract 25 from both sides.

$$mx+5x=m^{2}-25$$

Combine all terms containing x.

$$\left(m+5\right)x=m^{2}-25$$

Divide both sides by m+5.

$$\frac{\left(m+5\right)x}{m+5}=\frac{m^{2}-25}{m+5}$$

Dividing by m+5 undoes the multiplication by m+5.

$$x=\frac{m^{2}-25}{m+5}$$

Divide m^{2}-25 by m+5.

$$x=m-5$$

Solve for x

$$\left\{\begin{matrix}\\x=m-5\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&m=-5\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply m+5 by x.

$$mx+5x-m^{2}+25=0$$

Add m^{2} to both sides. Anything plus zero gives itself.

$$mx+5x+25=m^{2}$$

Subtract 25 from both sides.

$$mx+5x=m^{2}-25$$

Combine all terms containing x.

$$\left(m+5\right)x=m^{2}-25$$

Divide both sides by 5+m.

$$\frac{\left(m+5\right)x}{m+5}=\frac{m^{2}-25}{m+5}$$

Dividing by 5+m undoes the multiplication by 5+m.

$$x=\frac{m^{2}-25}{m+5}$$

Divide m^{2}-25 by 5+m.

$$x=m-5$$

Solve for m

$$m=-5$$

$$m=x+5$$