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Solve for m (complex solution)
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Solve for m
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\left(m+3\right)^{2}=\left(m+3\right)^{2}
Multiply m+3 and m+3 to get \left(m+3\right)^{2}.
m^{2}+6m+9=\left(m+3\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(m+3\right)^{2}.
m^{2}+6m+9=m^{2}+6m+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(m+3\right)^{2}.
m^{2}+6m+9-m^{2}=6m+9
Subtract m^{2} from both sides.
6m+9=6m+9
Combine m^{2} and -m^{2} to get 0.
6m+9-6m=9
Subtract 6m from both sides.
9=9
Combine 6m and -6m to get 0.
\text{true}
Compare 9 and 9.
m\in \mathrm{C}
This is true for any m.
\left(m+3\right)^{2}=\left(m+3\right)^{2}
Multiply m+3 and m+3 to get \left(m+3\right)^{2}.
m^{2}+6m+9=\left(m+3\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(m+3\right)^{2}.
m^{2}+6m+9=m^{2}+6m+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(m+3\right)^{2}.
m^{2}+6m+9-m^{2}=6m+9
Subtract m^{2} from both sides.
6m+9=6m+9
Combine m^{2} and -m^{2} to get 0.
6m+9-6m=9
Subtract 6m from both sides.
9=9
Combine 6m and -6m to get 0.
\text{true}
Compare 9 and 9.
m\in \mathrm{R}
This is true for any m.