Solve (i^-2)(1-2i)(3+4i)

$$( i ^ { - 2 } ) ( 1 - 2 i ) ( 3 + 4 i )$$

Evaluate

$$-11+2i$$

Solution Steps

Calculate i to the power of -2 and get -1.

$$-\left(1-2i\right)\left(3+4i\right)$$

Multiply -1 and 1-2i to get -1+2i.

$$\left(-1+2i\right)\left(3+4i\right)$$

Multiply -1+2i and 3+4i to get -11+2i.

$$-11+2i$$

Real Part

$$-11$$

Solution Steps

Calculate i to the power of -2 and get -1.

$$Re(-\left(1-2i\right)\left(3+4i\right))$$

Multiply -1 and 1-2i to get -1+2i.

$$Re(\left(-1+2i\right)\left(3+4i\right))$$

Multiply -1+2i and 3+4i to get -11+2i.

$$Re(-11+2i)$$

The real part of -11+2i is -11.

$$-11$$