Solve (d-3)^2-1/2=0

$$( d - 3 ) ^ { 2 } - \frac { 1 } { 2 } = 0$$

Solve for d

$$d=\frac{\sqrt{2}}{2}+3\approx 3.707106781$$

$$d=-\frac{\sqrt{2}}{2}+3\approx 2.292893219$$

Steps by Finding Square Root

Add \frac{1}{2} to both sides of the equation.

$$\left(d-3\right)^{2}-\frac{1}{2}+\frac{1}{2}=\frac{1}{2}$$

Subtracting \frac{1}{2} from itself leaves 0.

$$\left(d-3\right)^{2}=\frac{1}{2}$$

Take the square root of both sides of the equation.

$$d-3=\frac{\sqrt{2}}{2} d-3=-\frac{\sqrt{2}}{2}$$

Add 3 to both sides of the equation.

$$d-3-\left(-3\right)=\frac{\sqrt{2}}{2}-\left(-3\right) d-3-\left(-3\right)=-\frac{\sqrt{2}}{2}-\left(-3\right)$$

Subtracting -3 from itself leaves 0.

$$d=\frac{\sqrt{2}}{2}-\left(-3\right) d=-\frac{\sqrt{2}}{2}-\left(-3\right)$$

Subtract -3 from \frac{\sqrt{2}}{2}.

$$d=\frac{\sqrt{2}}{2}+3$$

Subtract -3 from -\frac{\sqrt{2}}{2}.

$$d=-\frac{\sqrt{2}}{2}+3$$

The equation is now solved.

$$d=\frac{\sqrt{2}}{2}+3 d=-\frac{\sqrt{2}}{2}+3$$