Solve (d)-4(2+x)=8quadtext{(e)}4(2-x)=8

$$( d ) - 4 ( 2 + x ) = 8 \quad \text { (e) } 4 ( 2 - x ) = 8$$

Solve for d, x

$$x=0$$

$$d=16$$

Solution Steps

Consider the second equation. Divide both sides by 4.

$$2-x=\frac{8}{4}$$

Divide 8 by 4 to get 2.

$$2-x=2$$

Subtract 2 from both sides.

$$-x=2-2$$

Subtract 2 from 2 to get 0.

$$-x=0$$

Divide both sides by -1. Zero divided by any non-zero number gives zero.

$$x=0$$

Consider the first equation. Insert the known values of variables into the equation.

$$d-4\times 2=8$$

Multiply -4 and 2 to get -8.

$$d-8=8$$

Add 8 to both sides.

$$d=8+8$$

Add 8 and 8 to get 16.

$$d=16$$

The system is now solved.

$$d=16 x=0$$