Solve (c-5)+(-9)+(-12)

$$( c - 5 ) + ( - 9 ) + ( - 12 )$$

Evaluate

$$c-26$$

Solution Steps

Subtract 9 from -5 to get -14.

$$c-14-12$$

Subtract 12 from -14 to get -26.

$$c-26$$

Differentiate w.r.t. c

$$1$$

Steps Using Derivative Rule for Sum

Subtract 9 from -5 to get -14.

$$\frac{\mathrm{d}}{\mathrm{d}c}(c-14-12)$$

Subtract 12 from -14 to get -26.

$$\frac{\mathrm{d}}{\mathrm{d}c}(c-26)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$c^{1-1}$$

Subtract 1 from 1.

$$c^{0}$$

For any term t except 0, t^{0}=1.

$$1$$