Solve (b+7)(b-2)(b+1)

$$( b + 7 ) ( b - 2 ) ( b + 1 )$$

Evaluate

$$\left(b-2\right)\left(b+1\right)\left(b+7\right)$$

Solution Steps

Apply the distributive property by multiplying each term of b+7 by each term of b-2.

$$\left(b^{2}-2b+7b-14\right)\left(b+1\right)$$

Combine -2b and 7b to get 5b.

$$\left(b^{2}+5b-14\right)\left(b+1\right)$$

Apply the distributive property by multiplying each term of b^{2}+5b-14 by each term of b+1.

$$b^{3}+b^{2}+5b^{2}+5b-14b-14$$

Combine b^{2} and 5b^{2} to get 6b^{2}.

$$b^{3}+6b^{2}+5b-14b-14$$

Combine 5b and -14b to get -9b.

$$b^{3}+6b^{2}-9b-14$$

Expand

$$b^{3}+6b^{2}-9b-14$$

Solution Steps

Apply the distributive property by multiplying each term of b+7 by each term of b-2.

$$\left(b^{2}-2b+7b-14\right)\left(b+1\right)$$

Combine -2b and 7b to get 5b.

$$\left(b^{2}+5b-14\right)\left(b+1\right)$$

Apply the distributive property by multiplying each term of b^{2}+5b-14 by each term of b+1.

$$b^{3}+b^{2}+5b^{2}+5b-14b-14$$

Combine b^{2} and 5b^{2} to get 6b^{2}.

$$b^{3}+6b^{2}+5b-14b-14$$

Combine 5b and -14b to get -9b.

$$b^{3}+6b^{2}-9b-14$$