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b^{2}+10b+25-\left(b+5\right)-6
Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(b+5\right)^{2}.
b^{2}+10b+25-b-5-6
To find the opposite of b+5, find the opposite of each term.
b^{2}+9b+25-5-6
Combine 10b and -b to get 9b.
b^{2}+9b+20-6
Subtract 5 from 25 to get 20.
b^{2}+9b+14
Subtract 6 from 20 to get 14.
b^{2}+10b+25-\left(b+5\right)-6
Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(b+5\right)^{2}.
b^{2}+10b+25-b-5-6
To find the opposite of b+5, find the opposite of each term.
b^{2}+9b+25-5-6
Combine 10b and -b to get 9b.
b^{2}+9b+20-6
Subtract 5 from 25 to get 20.
b^{2}+9b+14
Subtract 6 from 20 to get 14.