Solve (b+1)+(b-1)

$$( b + 1 ) + ( b - 1 )$$

Evaluate

$$2b$$

Solution Steps

Combine b and b to get 2b.

$$2b+1-1$$

Subtract 1 from 1 to get 0.

$$2b$$

Differentiate w.r.t. b

$$2$$

Steps Using Definition of a Derivative

Combine b and b to get 2b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(2b+1-1)$$

Subtract 1 from 1 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}b}(2b)$$

The derivative of ax^{n} is nax^{n-1}.

$$2b^{1-1}$$

Subtract 1 from 1.

$$2b^{0}$$

For any term t except 0, t^{0}=1.

$$2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2$$