Solve (abc)^0+a^0+bc^0

$$( a b c ) ^ { 0 } + a ^ { 0 } + b c ^ { 0 }$$

Differentiate w.r.t. b

$$1$$

Steps Using Derivative Rule for Sum

Calculate abc to the power of 0 and get 1.

$$\frac{\mathrm{d}}{\mathrm{d}b}(1+a^{0}+bc^{0})$$

Calculate a to the power of 0 and get 1.

$$\frac{\mathrm{d}}{\mathrm{d}b}(1+1+bc^{0})$$

Add 1 and 1 to get 2.

$$\frac{\mathrm{d}}{\mathrm{d}b}(2+bc^{0})$$

Calculate c to the power of 0 and get 1.

$$\frac{\mathrm{d}}{\mathrm{d}b}(2+b\times 1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$b^{1-1}$$

Subtract 1 from 1.

$$b^{0}$$

For any term t except 0, t^{0}=1.

$$1$$

Evaluate

$$b+2$$