Solve (a_{n}=-1/3n-31/3)

$$( a _ { n } = - \frac { 1 } { 3 } n - \frac { 31 } { 3 } )$$

Solve for n

$$n=-3a_{n}-31$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-\frac{1}{3}n-\frac{31}{3}=a_{n}$$

Add \frac{31}{3} to both sides.

$$-\frac{1}{3}n=a_{n}+\frac{31}{3}$$

Multiply both sides by -3.

$$\frac{-\frac{1}{3}n}{-\frac{1}{3}}=\frac{a_{n}+\frac{31}{3}}{-\frac{1}{3}}$$

Dividing by -\frac{1}{3} undoes the multiplication by -\frac{1}{3}.

$$n=\frac{a_{n}+\frac{31}{3}}{-\frac{1}{3}}$$

Divide a_{n}+\frac{31}{3} by -\frac{1}{3} by multiplying a_{n}+\frac{31}{3} by the reciprocal of -\frac{1}{3}.

$$n=-3a_{n}-31$$

Solve for a_n

$$a_{n}=\frac{-n-31}{3}$$