Solve for a
a=3-2i
a=3+2i
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\left(a-3\right)^{2}=-4
Subtracting 4 from itself leaves 0.
a-3=2i a-3=-2i
Take the square root of both sides of the equation.
a-3-\left(-3\right)=2i-\left(-3\right) a-3-\left(-3\right)=-2i-\left(-3\right)
Add 3 to both sides of the equation.
a=2i-\left(-3\right) a=-2i-\left(-3\right)
Subtracting -3 from itself leaves 0.
a=3+2i
Subtract -3 from 2i.
a=3-2i
Subtract -3 from -2i.
a=3+2i a=3-2i
The equation is now solved.
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