Solve for a
a=4q+3
Solve for q
q=\frac{a-3}{4}
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a+1-4q=4
Add -2 and 3 to get 1.
a-4q=4-1
Subtract 1 from both sides.
a-4q=3
Subtract 1 from 4 to get 3.
a=3+4q
Add 4q to both sides.
a+1-4q=4
Add -2 and 3 to get 1.
1-4q=4-a
Subtract a from both sides.
-4q=4-a-1
Subtract 1 from both sides.
-4q=3-a
Subtract 1 from 4 to get 3.
\frac{-4q}{-4}=\frac{3-a}{-4}
Divide both sides by -4.
q=\frac{3-a}{-4}
Dividing by -4 undoes the multiplication by -4.
q=\frac{a-3}{4}
Divide 3-a by -4.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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