Solve (a)^2=12*15

$$( a ) ^ { 2 } = 12 \cdot 15$$

Solve for a

$$a=6\sqrt{5}\approx 13.416407865$$

$$a=-6\sqrt{5}\approx -13.416407865$$

Steps by Finding Square Root

Multiply 12 and 15 to get 180.

$$a^{2}=180$$

Take the square root of both sides of the equation.

$$a=6\sqrt{5} a=-6\sqrt{5}$$

Steps Using the Quadratic Formula

Multiply 12 and 15 to get 180.

$$a^{2}=180$$

Subtract 180 from both sides.

$$a^{2}-180=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -180 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\left(-180\right)}}{2}$$

Square 0.

$$a=\frac{0±\sqrt{-4\left(-180\right)}}{2}$$

Multiply -4 times -180.

$$a=\frac{0±\sqrt{720}}{2}$$

Take the square root of 720.

$$a=\frac{0±12\sqrt{5}}{2}$$

Now solve the equation a=\frac{0±12\sqrt{5}}{2} when ± is plus.

$$a=6\sqrt{5}$$

Now solve the equation a=\frac{0±12\sqrt{5}}{2} when ± is minus.

$$a=-6\sqrt{5}$$

The equation is now solved.

$$a=6\sqrt{5} a=-6\sqrt{5}$$