Solve (a^mb^x)(-a^2)(-2ab)(-3a^2x)

$$( a ^ { m } b ^ { x } ) ( - a ^ { 2 } ) ( - 2 a b ) ( - 3 a ^ { 2 } x )$$

Evaluate

$$-6xa^{m+5}b^{x+1}$$

Steps Using Commutative Property of Multiplication

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$a^{m}b^{x}\left(-a^{2}\right)\left(-2\right)a^{3}b\left(-3\right)x$$

Multiply -2 and -3 to get 6.

$$a^{m}b^{x}\left(-a^{2}\right)\times 6a^{3}bx$$

Multiply -1 and 6 to get -6.

$$a^{m}b^{x}\left(-6\right)a^{2}a^{3}bx$$

To multiply powers of the same base, add their exponents. Add 2 and 3 to get 5.

$$a^{m}b^{x}\left(-6\right)a^{5}bx$$

Use the rules of exponents to simplify the expression.

$$\left(-6\right)^{1}a^{m}b^{x}x^{1}a^{5}b^{1}$$

Use the Commutative Property of Multiplication.

$$\left(-6\right)^{1}x^{1}a^{m}a^{5}b^{x}b^{1}$$

To multiply powers of the same base, add their exponents.

$$\left(-6\right)^{1}x^{1}a^{m+5}b^{x+1}$$

Multiply -6 times x.

$$\left(-6x\right)a^{m+5}b^{x+1}$$

Factor

$$-6xa^{m+5}b^{x+1}$$