Solve (a^3)^2+a^9div(-a^3)*1

$$( a ^ { 3 } ) ^ { 2 } + a ^ { 9 } \div ( - a ^ { 3 } ) \cdot 1$$

Evaluate

$$0$$

Short Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$a^{6}+\frac{a^{9}}{-a^{3}}\times 1$$

Express \frac{a^{9}}{-a^{3}}\times 1 as a single fraction.

$$a^{6}+\frac{a^{9}}{-a^{3}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply a^{6} times \frac{-a^{3}}{-a^{3}}.

$$\frac{a^{6}\left(-1\right)a^{3}}{-a^{3}}+\frac{a^{9}}{-a^{3}}$$

Since \frac{a^{6}\left(-1\right)a^{3}}{-a^{3}} and \frac{a^{9}}{-a^{3}} have the same denominator, add them by adding their numerators.

$$\frac{a^{6}\left(-1\right)a^{3}+a^{9}}{-a^{3}}$$

Do the multiplications in a^{6}\left(-1\right)a^{3}+a^{9}.

$$\frac{-a^{9}+a^{9}}{-a^{3}}$$

Combine like terms in -a^{9}+a^{9}.

$$\frac{0}{-a^{3}}$$

Zero divided by any non-zero term gives zero.

$$0$$

Factor

$$0$$