Solve (a^2-5)^2

$$( a ^ { 2 } - 5 ) ^ { 2 }$$

Expand

$$a^{4}-10a^{2}+25$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a^{2}-5\right)^{2}.

$$\left(a^{2}\right)^{2}-10a^{2}+25$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$a^{4}-10a^{2}+25$$

Evaluate

$$\left(a^{2}-5\right)^{2}$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a^{2}-5\right)^{2}.

$$\left(a^{2}\right)^{2}-10a^{2}+25$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$a^{4}-10a^{2}+25$$