Solve (a^2+a):a=[a+1]

$$( a ^ { 2 } + a ) : a = [ a + 1 ]$$

Solve for a

$$a\neq 0$$

Solution Steps

Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by a.

$$a^{2}+a=aa+a$$

Multiply a and a to get a^{2}.

$$a^{2}+a=a^{2}+a$$

Subtract a^{2} from both sides.

$$a^{2}+a-a^{2}=a$$

Combine a^{2} and -a^{2} to get 0.

$$a=a$$

Subtract a from both sides.

$$a-a=0$$

Combine a and -a to get 0.

$$0=0$$

Compare 0 and 0.

$$\text{true}$$

This is true for any a.

$$a\in \mathrm{R}$$

Variable a cannot be equal to 0.

$$a\in \mathrm{R}\setminus 0$$