Solve (a+b)(a-b)-(a+b)(a-b)

$$( a + b ) ( a - b ) - ( a + b ) ( a - b )$$

Evaluate

$$0$$

Solution Steps

Consider \left(a+b\right)\left(a-b\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$a^{2}-b^{2}-\left(a+b\right)\left(a-b\right)$$

Consider \left(a+b\right)\left(a-b\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$a^{2}-b^{2}-\left(a^{2}-b^{2}\right)$$

To find the opposite of a^{2}-b^{2}, find the opposite of each term.

$$a^{2}-b^{2}-a^{2}-\left(-b^{2}\right)$$

The opposite of -b^{2} is b^{2}.

$$a^{2}-b^{2}-a^{2}+b^{2}$$

Combine a^{2} and -a^{2} to get 0.

$$-b^{2}+b^{2}$$

Combine -b^{2} and b^{2} to get 0.

$$0$$

Factor

$$0$$

Solution Steps

Factor out common term 1-1 by using distributive property.

$$\left(1-1\right)\left(\text{Indeterminate}+\text{Indeterminate}+\text{Indeterminate}+\text{Indeterminate}\right)$$

Rewrite the complete factored expression.

$$\text{Indeterminate}$$