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a^{2}+6a+9-2\left(3a+4\right)
Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+3\right)^{2}.
a^{2}+6a+9-6a-8
Use the distributive property to multiply -2 by 3a+4.
a^{2}+9-8
Combine 6a and -6a to get 0.
a^{2}+1
Subtract 8 from 9 to get 1.
a^{2}+6a+9-2\left(3a+4\right)
Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+3\right)^{2}.
a^{2}+6a+9-6a-8
Use the distributive property to multiply -2 by 3a+4.
a^{2}+9-8
Combine 6a and -6a to get 0.
a^{2}+1
Subtract 8 from 9 to get 1.