Solve (a+1)(a-2)=a^2+a-2

$$( a + 1 ) ( a - 2 ) = a ^ { 2 } + a - 2$$

Solve for a

$$a=0$$

Steps for Solving Linear Equation

Use the distributive property to multiply a+1 by a-2 and combine like terms.

$$a^{2}-a-2=a^{2}+a-2$$

Subtract a^{2} from both sides.

$$a^{2}-a-2-a^{2}=a-2$$

Combine a^{2} and -a^{2} to get 0.

$$-a-2=a-2$$

Subtract a from both sides.

$$-a-2-a=-2$$

Combine -a and -a to get -2a.

$$-2a-2=-2$$

Add 2 to both sides.

$$-2a=-2+2$$

Add -2 and 2 to get 0.

$$-2a=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since -2 is not equal to 0, a must be equal to 0.

$$a=0$$