Solve (T_{1}-T_{2})*0.8=T_2^4*5.620-8*0.05

$$( T _ { 1 } - T _ { 2 } ) \times 0.8 = T _ { 2 } ^ { 4 } \times 5.620 - 8 \times 0.05$$

Solve for T_1

$$T_{1}=\frac{281T_{2}^{4}}{40}+T_{2}-0.5$$

Steps for Solving Linear Equation

Use the distributive property to multiply T_{1}-T_{2} by 0.8.

$$0.8T_{1}-0.8T_{2}=T_{2}^{4}\times 5.62-8\times 0.05$$

Multiply 8 and 0.05 to get 0.4.

$$0.8T_{1}-0.8T_{2}=T_{2}^{4}\times 5.62-0.4$$

Add 0.8T_{2} to both sides.

$$0.8T_{1}=T_{2}^{4}\times 5.62-0.4+0.8T_{2}$$

The equation is in standard form.

$$0.8T_{1}=\frac{281T_{2}^{4}}{50}+\frac{4T_{2}}{5}-0.4$$

Divide both sides of the equation by 0.8, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.8T_{1}}{0.8}=\frac{\frac{281T_{2}^{4}}{50}+\frac{4T_{2}}{5}-0.4}{0.8}$$

Dividing by 0.8 undoes the multiplication by 0.8.

$$T_{1}=\frac{\frac{281T_{2}^{4}}{50}+\frac{4T_{2}}{5}-0.4}{0.8}$$

Divide \frac{281T_{2}^{4}}{50}-0.4+\frac{4T_{2}}{5} by 0.8 by multiplying \frac{281T_{2}^{4}}{50}-0.4+\frac{4T_{2}}{5} by the reciprocal of 0.8.

$$T_{1}=\frac{281T_{2}^{4}}{40}+T_{2}-\frac{1}{2}$$