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Solve for R
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\left(R+4\right)^{2}-10+10=10
Add 10 to both sides of the equation.
\left(R+4\right)^{2}=10
Subtracting 10 from itself leaves 0.
R+4=\sqrt{10} R+4=-\sqrt{10}
Take the square root of both sides of the equation.
R+4-4=\sqrt{10}-4 R+4-4=-\sqrt{10}-4
Subtract 4 from both sides of the equation.
R=\sqrt{10}-4 R=-\sqrt{10}-4
Subtracting 4 from itself leaves 0.